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Ilia_Sergeevich [38]
3 years ago
14

Which equation is represented by the graph?

Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

I don't knowledge bro sorry

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A fair die is tossed 5 times. Let <img src="https://tex.z-dn.net/?f=%5Cdfrac%7Bm%7D%7Bn%7D" id="TexFormula1" title="\dfrac{m}{n}
Ray Of Light [21]

Answer:

m = 1

Step-by-step explanation:

We can suppose that the number we are looking for is for example 5.

(we can do so because the probability is the same for each number - it'sna fair dice)

For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).

For the second toss the probability we have 5 is again 1/6.

For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)

Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.

We can see that m = 1.

4 0
3 years ago
102 + 7y = 16<br> 15x + 8y 29<br> Is this consistent or inconsistent
mel-nik [20]

Answer:

Step-by-step explanation:

18y

6 0
3 years ago
Read 2 more answers
3/15divied by 4/9
Novay_Z [31]
Some things you can do is put them in decimals but the answer is 0.45
3 0
3 years ago
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Find the vector that has the same direction as 3, 2, −6 but has length 2.
Nata [24]

Answer:

The vector is \vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right).

Step-by-step explanation:

We can determine the equivalent vector (\vec r), dimensionless, by means of the following formula:

\vec r = \frac{\vec u}{\|\vec u\|} \cdot \|\vec r\| (1)

Where:

\vec u - Original vector, dimensionless.

\|\vec u\| - Norm of the original vector, dimensionless.

\|\vec r\| - Norm of the new vector, dimensionless.

The norm of the original vector is determined by the following definition:

\|\vec u\| = \sqrt{\vec u\,\bullet \,\vec u} (2)

If we know that \vec u = (3, 2, -6), then the norm of the original vector is:

\|\vec u\| = \sqrt{(3)\cdot (3)+(2)\cdot (2)+(-6)\cdot (-6)}

\|\vec u\| = 7

If we know that \|\vec r\| = 2, then the new vector is:

\vec r = \frac{2}{7}\cdot (3,2,-6)

\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)

The vector is \vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right).

7 0
3 years ago
Which choice is equivalent to the expression below?
morpeh [17]

Answer:

C

Step-by-step explanation:

As we can see, there are perfect squares in the first two expressions

thus, we have it that;

√(25x) = 5√x

√(4x) = 2√x

so we have the expression as;

5 √x - 2 √(x + 2 √x

= 5√x

3 0
2 years ago
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