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Ipatiy [6.2K]
3 years ago
5

Find the area of rectangles with the following dimensions.

Mathematics
1 answer:
seraphim [82]3 years ago
6 0

Answer:

I think this is the answer I hope I have helped you

Step-by-step explanation:

a

b

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Mrs. Rowan allotted 30 minutes at the
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The length of Rectangle A is 20 inches and the width is 4 inches. The length of Rectangle B is
astraxan [27]

Answer:

8 inches

Step-by-step explanation:

Let w be the width of rectangle B.

Since, both rectangles are similar.

Therefore, corresponding lengths and widths of rectangles A and B will be in proportion.

\therefore \frac{20}{40}  =  \frac{4}{w}  \\  \\  \frac{1}{2}  =  \frac{4}{w}  \\  \\ w = 2 \times 4 \\  \\ w = 8 \: inches

5 0
3 years ago
Read 2 more answers
Solve for x.<br> 5<br> 10<br> 12<br> 13
zysi [14]

Answer: B)  4 & 1/6

Nice work on getting the correct answer.

============================================================

Explanation:

x is opposite the marked acute angle

5 is opposite the corresponding acute angle

So x and 5 are proportional to each other. We can form the ratio x/5

Similarly, 10 and 12 are proportional to one another. We can form the ratio 10/12.

Set those ratios equal to each other and solve for x

x/5 = 10/12

12x = 5*10 ... cross multiply

12x = 50

x = 50/12 ...... divide both sides by 12

x = (25*2)/(6*2)

x = 25/6

x = (24+1)/6

x = 24/6 + 1/6

x = 4 + 1/6

x = 4 & 1/6 which shows why <u>choice B</u> is the answer.

Side note: 25/6 = 4.167 approximately

8 0
3 years ago
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