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3 years ago

.............................?.....?

Mathematics

1 answer:

Tamiku [17]3 years ago

5 0

you add 5=5 and that equals 18748 so ......... = 1000000 so yes is the answer

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F(x)=x^2 what is g(x)

Triss [41]

Answer: D

Step-by-step explanation:

Sometimes, it is hard to see which function fits g(x). We are given the point (4,1). Luckily, the point lies on g(x). We can plug in (4,1) into the g(x) equations and see which best fits.

A. Incorrect

$1=4(4)^2$

$1=4(16)$

$1\neq 64$

B. Incorrect

$1=\frac{1}{4} (4)^2$

$1=\frac{1}{4} (16)$

$1\neq 4$

C. Incorrect

$1=(\frac{1}{2}(4))^2$

$1=(2)^2$

$1\neq 4$

D. Correct

$1=(\frac{1}{4}(4))^2$

$1=(1)^2$

$1=1$

4 0

3 years ago

Evaluate the function. f(x) = 3x² – x Find f(10)

kirill [66]

Answer:

Step-by-step explanation:

<u>Function Evaluation</u>

Given a function f(x) as an explicit expression, finding f(x=a) implies substituting the value of x by a in every instance it occurs.

We are given the function:

$f(x)=3x^2-x$

It's required to find f(10). We replace the x for 10:

$f(10)=3*10^2-10$

Operating:

$f(10)=3*100-10$

$f(10)=300-10$

$f(10)=290$

Thus, f(10)=290

4 0

3 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

3 years ago

What are the answers?

aleksklad [387]

Answer:

x= -1 and 0

Step-by-step explanation:

5 0

3 years ago

What is digit definition

Ilia_Sergeevich [38]

Answer:

any of the numerals from 0 to 9, especially when forming part of a number.

5 0

4 years ago

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