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2 years ago

Helppppp pleasseeeee

Mathematics

1 answer:

Hitman42 [59]2 years ago

4 0

Answer:

Step-by-step explanation:

(3, 1) (6, -1)

(-1 -1)/(6-3) = -2/3

y - 1 = -2/3(x - 3)

y - 1 = -2/3x + 2

y = -2/3x + 3

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74 is a rational number but not a whole number. 74 is a whole number but not a rational number. 74 is a whole number and a ratio

Lady_Fox [76]

Answer:

Option C: 74 is both a whole number and a rational number.

Step-by-step explanation:

A rational number is defined as a number which can be written as a fraction of two integers, an integer, a whole number and a natural number. The integer could be positive or negative.

Examples include -1/4, 1/2, 12

So it's obvious that the given number of 74 is a rational number.

Now, a whole number is simply a non - negative integer.

An integer is a number that is not a fraction.

Thus, examples of whole numbers are 0, 1, 2, 3, 4...

So 74 is clearly a whole number.

Therefore, we can conclude that 74 is both a whole number and a rational number.

5 0

2 years ago

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
$

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
$\frac{-77+21i}{130}$

7 0

3 years ago

Can someone please help me with this question? I don't know how? What is the volume of a rectangular prism with a length of 2x –

lesantik [10]

Volume is legnth times widht times height
lenght=2x-1
width=x-2
height=x+1
multiply all together
use mass distributive property
distributive=a(b+c)=ab+ac so extending that
(a+c)(c+c)=(a+b)(c)+(a+b)(d) then keep distributing so
(2x-1)(x-2)(x+1)
do each one seperately
do the first two first and put the other one (x+1) to the side for later
(2x-1)(x-2)=(2x-1)(x)+(2x-1)(-2)=(2x^2-x)+(-4x+2)=2x^2-5x+2
then do the other one
(x+1)(2x^2-5x+2)=(x)(2x^2-5x+2)+(1)(2x^2-5x+2)=(2x^3-5x^2+2x)+(2x^2-5x+2)=2x^3-3x^2-3x+2

the lasst form is 2x^3-3x^2-3x+2

3 0

3 years ago

Plz help I'm just having a brain fart right now<br><br>

Wittaler [7]

Answer:

x=11

Step-by-step explanation:

For extra help the second answer is: 7a(3-a)

4 0

3 years ago

Simplify the expression 7(3+2p+7).

ipn [44]

Answer: 14p +70

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers