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VMariaS [17]
2 years ago
13

What is the answer? ​

Mathematics
2 answers:
Dimas [21]2 years ago
4 0

Answer:

10

Step-by-step explanation:

german2 years ago
4 0

Answer:

5

Step-by-step explanation:

\triangle ACB \cong \triangle DCE... (given) \\\\\implies m\angle A = m\angle D... (cact) \\\\\therefore 50\degree = (10x) \degree \\\\\therefore 50 = 10x\\\\\therefore \frac{50\degree}{10}= x \\\\\therefore 5 = x \\\\x = 5

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Let A be a 4 x 5 matrix and Let B be a 4 x 4 matrix. Suppose you were asked to multiply matrix A times matrix B. When multiplied
VMariaS [17]

Answer:

b. false

Step-by-step explanation:

when multiplying matrixes the number of columns of the first matrix must be equal as the number of rows of the second matrix, and since here matrix A has 4 columns but matrix B has 5 rows they can't be multiplied

8 0
2 years ago
Calculate δe, if q= 0.769 kj and w= -860 j .
Andreyy89
<span>Best Answer: 1) Q is positive therefore the process is endothermic. .769kj+-.810kj=-.041kj 2) Heat is released meaning it is exothermic. -66.9kj+45=-21.9kj 3) 7.29kj. Endothermic.</span>
7 0
3 years ago
Daniel’s school is selling tickets to the annual talent show. On the first day of ticket sales, the school sold 8 senior citizen
zavuch27 [327]

Answer:

the answer is 17

Step-by-step explanation:

You divide 8 and 136 and get 17, you multiply 17 and 8 to double check your answer, Hope this helps :P!

3 0
3 years ago
Read 2 more answers
Simplify 8k+2+4k+(-3k)+5
Rzqust [24]
8k+4k-3k=9k
2+5=7
9k+7
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
2 years ago
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