Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)
(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)
(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)
(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.
Given:
To find:
The simplified fraction.
Solution:
Step 1: Simplify the numerator
Step 2: Simplify the denominator
Step 3: Using step 1 and step 2
Step 4: Using fraction rule:
Cancel the common factor r and t², we get
Cancel the common factors 16 and 3 on both numerator and denominator.
The simplified fraction is 
.
Answer:
w = 8
Step-by-step explanation:
Based on the altitude theorem of a right triangle, we have:
w + 4 = √(24*6)
w + 4 = √144
w + 4 = 12
w + 4 - 4 = 12 - 4
w = 8
