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maw [93]
3 years ago
5

In the image, two circles are centered at A The circle containing was dilated to produce the circle containing B’.What is the sc

ale factor of the
dilation?

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

The scale factor of the  dilation is 1/2

Step-by-step explanation:

we have that

The radius of the circle containing B is

r_1=2\ units

The radius of the circle containing B' is

r_2=1\ units

The dilation of circle containing B to circle containing B'  is a reduction

To find out the scale factor divide the radius of circle containing B'  by the radius of the circle containing B

so

\frac{r_2}{r_1}= \frac{1}{2}

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Juan pays a one-time fee of $30.
Nastasia [14]

Answer:

Step-by-step explanation:

A. c=30+45(h)

B. 30+45(6.5)= 30+292.50= 322.50

He pays a set rate of $30.00. He also pays a charge of $45 an hour for work. The electrician worked 6.5 hours. Take the 45 and multiply that by the 6.5 hours to get $292.50. Take that charge and add the set fee of $30. You get a total of $322.50 he will pay for the electrician.

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3 years ago
The country of benin in west Africa has a population of 9.05 million people. The population is growing at a rate of 3.1% each ye
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2 years ago
Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together the
klasskru [66]

The rate charged per hour by each mechanic was:  x = 75 $ / hr and y = 115 $ / hr.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given;

The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours.

Together they charged a total of $3225.

For this case we have the following variables:

x be the amount of $ / hr that the mechanic obtains 1.

y be the amount of $ / hr obtained by mechanic 2.

An equation to express this would be:

x + y = 190

20x + 15y = 3225

Solving the system of equations we have:

20x + 15(190 -x) = 3225

20x + 2850 - 15x = 3225

5x = 375

x = 75

simililary

y = 190 - x

y = 115

Hence, the rate charged per hour by each mechanic was:

x = 75 $ / hr

y = 115 $ / hr

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Find the distance between each pair of parallel line<br>y=x-6 and y=x+8
myrzilka [38]
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