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3 years ago

Are those two expression equivalent when x=10 5(3x+8) 8(x+8

Mathematics

2 answers:

Margarita [4]3 years ago

8 0

Let's solve for x!
5(3x+8)=8(x+8)
15x+40=8x+64
7x=24
x=24/7

x= 24/7, not 10
So the answer is no

My name is Ann [436]3 years ago

6 0

No, the first choice equals 190 and the second 144.

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Factor using a GCF:<br> 16xy2+28xy+8y

Lorico [155]

Answer:

4y( 4xy + 7x +2)

Step-by-step explanation:

16xy^2+28xy+8y

16xy^2 =2*2*2*2*x*y*y

28xy = 2*2*7 *x*y

8y = 2*2*2*y

The common factors are 2*2*y = 4y

2*2*2*2*x*y*y + 2*2*7 *x*y+2*2*2*y

2*2*y( 2*2*x*y + 7 *x+2)

4y( 4xy + 7x +2)

7 0

2 years ago

Find dy/dx of y=csc(square root of x)

Vitek1552 [10]

Answer:

$y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}$

Step-by-step explanation:

y = csc x

y' = -cot x csc x

$y = \csc \sqrt{x}$

$y' = \dfrac{d}{dx} [\csc \sqrt{x}]$

$y' = (-\cot x \csc x) \dfrac{d}{dx} \sqrt{x}$

$y' = (-\cot x \csc x) \dfrac{d}{dx} x^{\frac{1}{2}}$

$y' = (-\cot x \csc x) \dfrac{1}{2} x^{-\frac{1}{2}}$

$y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}$

5 0

2 years ago

Mr Binnix wife is older than her sister by 2 years if their ages add up to 52 how old is each sister? Let c represent Leigh Ann’

Mazyrski [523]

Answer:

the older sister is 27 and the younger is 25.

Step-by-step explanation:

C+2=Y

C+Y=52

2C+2=52

2C=50

C=25

25+2=Y

Y=27

5 0

2 years ago

Write a quadratic function for each graph described.

user100 [1]

Answer:

$y=2x^2-\frac{4}{3}x-\frac{10}{3}$

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

we can write the equation of the parabola as

$y=a(x+1)(x-\frac{5}{3})$

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

$40=a(5+1)(5-\frac{5}{3})$

$40=a(6)(\frac{10}{3})$

$40=20a\\a=2$

substitute

$y=2(x+1)(x-\frac{5}{3})$

apply distributive property

$y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}$

see the attached figure to better understand the problem

6 0

3 years ago

Anonymous 3 years ago

amm1812

Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.

Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.

From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH

Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees

Recall that mHFG + mACB = 90 degrees

Thus, mHFG + mACB = mHFG + mDFH

Therefore, mACB = mDFH.

5 0

3 years ago