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3 years ago

2x² - 5/6 x +1/12 PLS ANS

Mathematics

2 answers:

Pavel [41]3 years ago

3 0

Answer:

$2x^{2} -\frac{1}{3}$

Step-by-step explanation:

1) Collect like terms.

$2x^{2} +(-\frac{5}{6} +\frac{1}{2} )$

2) Simplify.

$2x^{2} -\frac{1}{3}$

Karolina [17]3 years ago

3 0

Answer:

Step-by-step explanation:

$2x^{2} - \frac{5}{6}x + \frac{1}{12}$

Multiply the whole expression by 12

$= 12*2x^{2} - 12*\frac{5}{6}x + 12*\frac{1}{12}\\\\= 24x^{2}-2*5x + 1\\\\=24x^{2}-10x + 1$

Sum = - 10

Product = 24

Factors = -6 , -4 {(-6)+(-4) = -10 & (-6)*(-4) = 24}

24x² - 10x + 1 = 24x² -6x - 4x + 1 {Rewrite the middle term using the factors}

= (24x² - 6x) - 4x + 1

= 6x (4x - 1) - (4x - 1)

= (4x - 1)(6x - 1)

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Between which two consecutive integers does the negative square root of 20 lie

sertanlavr [38]

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3 years ago

What is the solution to this system of linear equations?

Eva8 [605]

8x+y=3
-8x -8x
--------------
y=-8x+3

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Substitute -8x+3 in place of y
-8x+3=7/2x+3
+8x +8x
-----------———
3= 11.5x+3
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—— ——
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X=0

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Check
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4 years ago

"You are dating Moon rocks based on their proportions of uranium-238 (half-life of about 4.5 billion years) and its ultimate dec

Olenka [21]

Step-by-step explanation:

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 41% = t

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$N_o$ = initial mass of isotope = x

N = mass of the parent isotope left after the time, (t) = 59% of x = 0.59x

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$\lambda$ = rate constant

Now put all the given values in this formula, we get

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The age a rock is 3.4 billion years.

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 35%= t

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$N_o$ = initial mass of isotope = x

N = mass of the parent isotope left after the time, (t) = 65% of x = 0.65x

$t_{\frac{1}{2}}$ = half life of the isotope = 4.5 billion years

$\lambda$ = rate constant

Now put all the given values in this formula, we get

$0.65x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}$

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The age a rock is 2.8 billion years.

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4 years ago

8÷2(2+2)<br>what is the anwer<br>

Colt1911 [192]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Please help me find an equation for this

satela [25.4K]

Answer:

The equation that represents this situation is x + 3x + (x - 4) + 2(x - 4) = 72, where x is Erik's age

Step-by-step explanation:

Let us solve the question

Assume that Erik is x years old

∵ Erik is x years old

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→ That means x = $\frac{1}{3}$ Dawn

∴ x = $\frac{1}{3}$ Dawn

→ Multiply both sides by 3

∴ 3x = Dawn

∴ Dawn is 3x years old

∵ Jiro is 4 years younger than Erik

→ That means Jiro = x - 4

∴ Jiro is (x - 4) years old

∵ Alita is 2 times as old as Jiro

→ That means Alita = 2 × (x - 4)

∴ Alita = 2 × (x - 4)

∴ Alita is 2(x - 4) years old

∵ The sum of all their ages is 72

→ That means add their ages and equate the sum by 72

∴ Erike's age + Dawn's age + Jiro's age + Alita's age = 72

∴ x + 3x + (x - 4) + 2(x - 4) = 72

The equation that represents this situation is x + 3x + (x - 4) + 2(x - 4) = 72, where x is Erik's age

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3 years ago