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Margaret [11]
3 years ago
7

Mike is 4 years older than his sister Olivia. together they are 20 years old. How old is Olivia?

Mathematics
2 answers:
maw [93]3 years ago
5 0

Answer: Olivia is 8 years old.

Step-by-step explanation:

"O" stands for Olivia

O+4 = M

O + O+4 = 20

2O +4=20

2O=16

2O/2 = 16/2

O = 8

Mike is 4 years older, so Mike is 12 years old

12+8 = 20

MrRissso [65]3 years ago
3 0

Answer:

Olivia is 24 years old

step by step

because Olivia is 20 years old and Mike is 4 years older than her so Olivia is 24 years old

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Is 8.15 a natural number whole number integer rational irrational or real number ?
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Answer:

Rational

Step-by-step explanation:

A rational number is a number expressed as a fraction. So the number could be a decimal or percent.

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the royals softball team played 75 games and won 55 of them. what percent of the games did they lose?
Yuki888 [10]

Answer:

Total played games = 75

Total won = 55

Total lose = 75 - 55

= 20

℅ of the games they lose = (20/75) x 100

= 400/15

= 80/3

= 26.66(27 approx)

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Step-by-step explanation:

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3 years ago
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What is 19/25 as a decimal
Ivan
Okay, so u just divide numerator and the denominator... you get 0.76.
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3 years ago
Which point is on the circle with center (-3,-1) that contains the point (1, 2)?
jasenka [17]

Answer:

Any point that is 5 units from the center

Step-by-step explanation:

The given circle is centered at;

(-3,-1) and contains (1,2).

The radius is given by:

r =  \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

We substitute the point to get:

r =  \sqrt{(1- - 3)^2 +(2- - 1)^2}

r =  \sqrt{4^2 +3^2}

r =  \sqrt{25}  = 5

Therefore any point that is 5 units from the center lies on this circle.

5 0
3 years ago
1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel
Lana71 [14]

Answer:

a)  \overline{AB} = 8 in

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. \overline{AB} = 10 in

c)  When the length of AB = 10.2 in. and BC = 3.7 in.  \overline {AC}  = 6.5 in

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. \overline {BC} =  1\frac{1}{2} in

Step-by-step explanation:

a) When the length of AC = 5 in. and CB = 3 in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 5 in. + 3 in. = 8 in.

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 6\frac{1}{2} in.+ 3\frac{1}{2} in. = 10 in.

c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;

The length of \overline {AC} = AB - BC (converse of the segment addition postulate)

Therefore;

\overline {AC} = 10.2 in.+ 3.7 in. = 6.5 in.

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. we have;

The length of \overline {BC} = AB - AC (converse of the segment addition postulate)

Therefore;

\overline {BC} = 4\frac{3}{4} in. -  3\frac{1}{4} in.=  1\frac{1}{2} in.

6 0
3 years ago
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