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Gemiola [76]
2 years ago
5

HELP!!! WILL GIVE BRAINLIEST TO THE CORRECT ANSWER (which is not rhombic prism Just BTW)

Mathematics
1 answer:
grandymaker [24]2 years ago
6 0

Answer:

square prism

Step-by-step explanation:

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Which Answer is a solution to the inequality?
marusya05 [52]

Answer:

The answer is D) (-1, -1)

Step-by-step explanation:

In order to find which answer is a solution, you have to put the ordered pair in for their given variables. If it produces a true statement, then it is a solution. In this case, D is the only one that produces a true statement.

2x + y > -4

2(-1) + (-1) > -4

-2 - 1 > -4

-3 > -4 (TRUE)

8 0
3 years ago
A cylindrical tank has a base of diameter 12 ft and height 5 ft. The tank is full of water (of density 62.4 lb/ft3).(a) Write do
saw5 [17]

Answer:

a.  71884.8 π lb/ft-s²∫₀⁵(9 - y)dy

b.  23961.6 π lb/ft-s²∫₀⁵(5 - y)dy

c. 99840π lb/ft-s²∫₀⁶rdr

Step-by-step explanation:

.(a) Write down an integral for the work needed to pump all of the water to a point 4 feet above the tank.

The work done, W = ∫mgdy where m = mass of cylindrical tank = ρA([5 + 4] - y) where ρ = density of water = 62.4 lb/ft³, A = area of base of tank = πd²/4 where d = diameter of tank = 12 ft.( we add height of the tank + the height of point above the tank and subtract it from the vertical point above the base of the tank, y to get 5 + 4 - y) and g = acceleration due to gravity = 32 ft/s²

So,

W = ∫mgdy

W = ∫ρA([5 + 4] - y)gdy

W = ∫ρA(9 - y)gdy

W = ρgA∫(9 - y)dy

W = ρgπd²/4∫(9 - y)dy

we integrate W from  y from 0 to 5 which is the height of the tank

W = ρgπd²/4∫₀⁵(9 - y)dy

substituting the values of the other variables into the equation, we have

W = 62.4 lb/ft³π(12 ft)² (32 ft/s²)/4∫₀⁵(9 - y)dy

W = 71884.8 π lb/ft-s²∫₀⁵(9 - y)dy

.(b) Write down an integral for the fluid force on the side of the tank

Since force, F = ∫PdA where P = pressure = ρgh where h = (5 - y) since we are moving from h = 0 to h = 5. So, P = ρg(5 - y)

The differential area on the side of the tank is given by

dA = 2πrdy

So.  F = ∫PdA

F = ∫ρg(5 - y)2πrdy

Since we are integrating from y = 0 to y = 5, we have our integral as

F = ∫ρg2πr(5 - y)dy

F = ∫ρgπd(5 - y)dy    since d = 2r

substituting the values of the other variables into the equation, we have

F = ∫₀⁵62.4 lb/ft³π(12 ft) × 32 ft/s²(5 - y)dy

F = 23961.6 π lb/ft-s²∫₀⁵(5 - y)dy

.(c) How would your answer to part (a) change if the tank was on its side

The work done, W = ∫mgdr where m = mass of cylindrical tank = ρAh where ρ = density of water = 62.4 lb/ft³, A = curved surface area of cylindrical tank = 2πrh  where r = radius of tank, d = diameter of tank = 12 ft. and h =  height of the tank = 5 ft and g = acceleration due to gravity = 32 ft/s²

So,

W = ∫mgdr

W = ∫ρAhgdr

W = ∫ρ(2πrh)hgdr

W = ∫2ρπrh²gdr

W = 2ρπh²g∫rdr

we integrate from r = 0 to r = d/2 where d = diameter of cylindrical tank = 12 ft/2 = 6 ft

So,

W = 2ρπh²g∫₀⁶rdr

substituting the values of the other variables into the equation, we have

W = 2 × 62.4 lb/ft³π(5 ft)² × 32 ft/s²∫₀⁶rdr

W = 99840π lb/ft-s²∫₀⁶rdr

7 0
3 years ago
Find the value of 7 + b when b= 15.<br><br> Help ?
Lisa [10]

7 + b

= 7 + 15

= <u>22</u>

<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u>!</u>

4 0
2 years ago
Read 2 more answers
D. 3, 7, 13, 21, 31.<br> Cual es la expresión algebraica??
ololo11 [35]

Answer:

d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??

Step-by-step explanation:

d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??d. 3, 7, 13, 21, 31.

Cual es la expresión algebraica??

3 0
2 years ago
Heeeeeeeelpppppppppp​
Mekhanik [1.2K]

Answer:

14.83 feet

Step-by-step explanation:

c^{2} =a^{2} +b^{2}

a=\sqrt{16^{2}-6^{2}  }

a=14.83 feet

8 0
2 years ago
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