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erastovalidia [21]
3 years ago
13

A parking garage in the city charges $2.75 for the first hour and S1 25 for each additional hour or part thereof. What is the ma

ximum time in hours, x, that Tony can park his car at the garage if he wants to
pay less than $8?
A Or<4
BO2<5
CO2<6
Dr<7
Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer: The first hour is free, and the rest charges is $2.50

Let x be the time.

Let y be the total

Your equation will look like

When x < 2, y = 0

When x > 1, y = $2.50(x)

So:

1 < x < ∞ for hours, then equation will look like:

y = total amount

$2.50 is cost (remember that the first hour is for free, and so you subtract $2.50 from the total.

$2.50x - $2.50 = y should be your equation.

hope this helps

Step-by-step explanation:

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dusya [7]

Answer:

The median and IQR

Step-by-step explanation:

4 0
2 years ago
1. Gavin and Seiji both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. Ho
Gre4nikov [31]
Let x = the amount that Seini earned
Then x + 25 = the amount that Gavin
The amount Gavin earned would also = 425 - x (your directions asked you to have 2 equations.)
Together they earned 425:
x + (x + 25) = 425
2x + 25 = 425
2x = 400
Now divide both sides by 2 to find x.

Use all of this data to satisfy the directions.
8 0
3 years ago
PLEASE HELP ME: the ratio of cars to trucks on a highway at any given time is 12 to 8. If there are always more than 105 cars on
andre [41]

Answer:

70

Step-by-step explanation:

First, set up the ratio of c:t, which is 12:8. Then set up your new ratio of c:t, which is 105:?. The way I find the easiest is to divide 105 by 12, which is 8.75, then multiply that by 8, which is 70. To check if it's right, just divide 12 by 8, and 105 by 70, and if they're the same number, you've got it right.

Ps. I'm guessing you meant to ask the minimum number of trucks, not cars.

5 0
2 years ago
6f+f(f+2)+3 f*to the 2nd power-4f​
EastWind [94]

Answer:

the answer is f^2+8f+3^-4f

8 0
3 years ago
Three vertices of the trapezoid are A(4d,4e), B(4f,4e), and C(4g,0). The fourth vertex lies on the origin. Find the midpoint of
satela [25.4K]
We have that

point C and point D have y = 0-----------> (the bottom of the trapezoid).

point A and point B have y = 4e ---------- > (the top of the trapezoid)

the y component of  midpoint would be halfway between these lines
 y = (4e+ 0)/2 = 2e. 

<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.

x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g. 

</span>therefore

the midpoint of the midsegment is (d + f + g, 2e)
8 0
3 years ago
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