Listing is for finite or "countable" sets -whatever that means to you.
49. list x-value(s) for which the equality holds
50. 0,1,2,3,4 since 5!=120
51. 0,1,2,3,4,5,6,7
52.a. P (10,3) order matters
b. P (6,3)
c. could be answer to a but I am not entirely sure.
Follow for solutions.
-3 + 8 would be an option
Answer:
438,012 ways.
Step-by-step explanation:
We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.
Since the letters and digits can be repeated, so we will use fundamental principal of counting.
For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.
We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.
So we can choose coupon code is following ways:

Therefore, we can choose coupon codes in 438,012 ways.
Answer:
The shorter base is 3
Step-by-step explanation:



Answer: 706.5
Step-by-step explanation:
First you have to square the radius. So for this question you multiply 5x5. That makes 25. Then you multiply that with pi ( 3.14 ) and that makes 78.50. Next you multiply it by 9, that makes 706.5.