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Artist 52 [7]
3 years ago
14

Which pair of angles shares ray a as a common side

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
Answer: Is the last one. D

Hope this helps
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What is 500000 and 60000000 as a decimal
Juliette [100K]

The only way to make a decimal out of either of those numbers is to write a decimal point with some zeros after it.

500,000  =  500,000.000

60,000,000  =  60,000,000.00000

etc.

3 0
3 years ago
A used automobile dealership recently reduced the price of a used compact car by 6%. If the price of the car before discount was
Alchen [17]

Answer:

The discount = $1,128

New price = $17,672

Step-by-step explanation:

Price of car before discount = $18,800

Discount given = 6% of price of car

Discount value in dollars = 6% of $18,800 = 6/100*$18,800 = $1,128

Thus, the discount is $1,128

New price = Price of car before discount - discount = $18,800- $1,128

New price = $17,672

7 0
3 years ago
A line passes through the point (-4,7) and has a slope of 5/2.
hoa [83]

Answer:

(9,20)

Step-by-step explanation:

9 and 20 together... (9,20)

8 0
2 years ago
The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t
wolverine [178]

Answer:

a) The implied differential equation is \frac{dN}{725 - N} = kdt

b) The general equation is N = 725 - C e^{-kt}

c) The particular equation is N = 725 - 325 e^{-0.49t}

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, \frac{dN}{dt} \alpha (725 - N(t))

\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt

Integrating both sides of the equation

\int {\frac{1 }{725 - N}} \, dN  = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}

When t = 0, N = 400

400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325

When t = 3,  N = 650

650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49

The equation for the population becomes:

N = 725 - 325 e^{-0.49t}

At t = 5, the population becomes:

N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697

N(5) = 700 ( to the nearest 50)

6 0
3 years ago
Evaluate.<br><br><br> -1<br> (1/5) ⋅ 4^0<br><br><br><br><br> 0<br><br> 1<br><br> 5<br><br> 20
Ierofanga [76]

Answer:

the answer is 5 I think I hope

5 0
2 years ago
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