All categories

3 years ago

A circle has a radius of 6. An arc in this circle has a central angle of 48 degress. What is the length of the arc?

Mathematics

2 answers:

aalyn [17]3 years ago

5 0

The answer would be 1.6pi

notsponge [240]3 years ago

3 0

Answer: $1.6\pi$

Step-by-step explanation:

If a circle has a radius of 6, then the perimeter of the circle is 12pi, or about 37.68. A circle has 360 degrees. Thus, the arc takes up 48/360 of the circle. Thus, simply multiply $\frac{48}{360} * 12\pi$ to get 5.024 or 1.6pi.

Hope it helps <3

You might be interested in

Can 16, 19, and 34 form a triangle? Show your work.

I am Lyosha [343]

yes, since a+b > c for all sides

3 0

3 years ago

GIVING BRAINLIEST FOR BEST ANSWER!

Nataly_w [17]

The answer to the question is C.

5 0

2 years ago

Read 2 more answers

Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>

Sveta_85 [38]

Trigonometric Formula's:

$\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}$

$\boxed{ \sf tan\theta = \frac{sin\theta}{cos\theta} }$

Given to verify the following:

$\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a$

$\texttt{\underline{rewrite the equation}:}$

$\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )$

$\texttt{\underline{apply distributive method}:}$

$\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)$

$\texttt{\underline{simplify the following}:}$

$\rightarrow \sf 2cos^2 a + sin^2 a$

$\texttt{\underline{rewrite the equation}:}$

$\rightarrow \sf 2(1 - sin^2a ) + sin^2 a$

$\texttt{\underline{distribute inside the parenthesis}:}$

$\rightarrow \sf 2 - 2sin^2a + sin^2 a$

$\texttt{\underline{simplify the following}} :$

$\rightarrow \sf 2 - sin^2a$

Hence, verified the trigonometric identity.

7 0

1 year ago

Read 2 more answers

Solve for x. <br><br>x/4 = -1

Lyrx [107]

Answer: -4

Step-by-step explanation: -4/4 = -1

Please mark Brainliest!

8 0

3 years ago

Read 2 more answers

Is 1.29 more than 1.202

steposvetlana [31]

Yes because 9 is bigger than 0.

5 0

2 years ago

Read 2 more answers