There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Answer:
Step-by-step explanation:
Speed = distance/time
Speed = 50/4
Speed = 12.5
Your answer is C!!!
The slope-intercept form of a line is the following:
In this form, 
is the shape and 
is the y-intercept. Your line written in this form is
which implies that the slope is 5 and the y-intercept is -2.
Answer:
Can i see the actual problem so i can get an accurate answer
Step-by-step explanation:
2y/5 is the same thing as 2/5 times y so
14=2/5(y) then you divide both sides by y and you get
14/y=2/5 then from there multiply both sides by 1/14 to get
y=0.03
