<span>Trinomial Ax^2 + Bx + C is perfect square if:
A > 0
C > 0
B = ±2√A√C

36b^2 − 24b − 16
C < 0

4a^2 − 10a + 25
2√A√C = 2*2*5 = 20,
B = −10

16x^2 + 24x − 9
not perfect square,
C < 0

4x^2 − 12x + 9
perfect square:
A>0,
C>0,
2√A√C
= 2*2*3
= 12
= -B
= (2x − 3)^2
hope this helps</span>

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3 years ago

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Find the equation of a line parallel to the line 2x-y-9=0 and passing through the point of intersection of the lines 5x+y+4=0 an

Cerrena [4.2K]

Answer:

$y=2x-3$

Step-by-step explanation:

1. Using the point of intersections, we use the substitution method to find the coordinates of the line parallel to $2x-y-9=0$

$5x+y+4=0$

$y= -4-5x$

substituting the value of y in $2x+3y=1$ :

$2x +3(-4-5x)=1\\\\2x-12-15x-1=0\\-13x=13x\\x= \frac{13}{-13}= -1$

substituting x=-1 in y= -4-5x:

$y= 1$ (upon solving, you should get this)

$(x,y)= (-1,1)$

2. Using y=mx+c and making y the subject of the formula 2x-y-9=0 and using the coordinate we found earlier, we will find the equation of the parallel line. (We make y the subject of the formula to find the gradient)

$2x-y-9=0\\2x-9=y\\y= 2x-9$