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anastassius [24]

3 years ago

13

HELPPPPPPPPPPPP]PPPPPP

1 answer:

Alinara [238K]3 years ago

6 0

1) negative linear association 2)non linear association (haven’t done in a while so not completely sure)

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Kylie buys a ceramic case priced at $75. Shipping and handling are an additional 9 2/5% of the price. How much shopping and hand

salantis [7]

$\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
75&100\\
x&9\frac{2}{5}
\end{array}\implies \cfrac{75}{x}=\cfrac{100}{9\frac{2}{5}}\implies \cfrac{75}{x}=\cfrac{100}{\frac{9\cdot 5+2}{5}}$

$\bf \cfrac{75}{x}=\cfrac{\frac{100}{1}}{\frac{47}{5}}\implies \cfrac{75}{x}=\cfrac{100}{1}\cdot \cfrac{5}{47}\implies \cfrac{75}{x}=\cfrac{500}{47}\implies 75\cdot 47=500\cdot x
\\\\\\
\cfrac{3525}{500}=x\implies \cfrac{141}{20}=x\implies 7.05=x$

7 0

3 years ago

Find the area of the rhombus.<br> 4.32 m2<br> 2.16 m2<br> 1.08 m2<br> 1.05 m2

S_A_V [24]

Answer:

Step-by-step explanation:

Alright, lets get started.

The part of the diagonals are given as 0.9 m and 1.2 m.

The diagonals of rhombus intersect each other.

Hence the length of diagonals will be : $0.9*2=1.8$ and $1.2*2=2.4$

The formula of area of rhombus is : $\frac{pq}{2}$ where p and q are the length of diagonals.

So plugging the values of diagonals in formula, the area will be :

Area = $\frac{1.8*2.4}{2}$

Area = $\frac{4.32}{2}$

Area = $2.16 \ m^2$ ................. Answer

Hope it will help :)

6 0

3 years ago

Find the product (3x + 2)(x ^ 3 - 4x ^ 2 + 7)

schepotkina [342]

Answer:

see attachment

Step-by-step explanation:

5 0

3 years ago

You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th

Sonja [21]

Answer:

$Quarters = 41$

$Dimes = 18$

Step-by-step explanation:

Given

$Coins = 59$

$Worth = \$12.05$

$d = dimes$

$q = quarters$

Required

The number of each coin

The total coins can be represented as:

$d + q = 59$

$1\ quarter = \$0.25 \\ 1\ dime = \$0.10$

So, the worth of the coin is:

$0.25q + 0.10d = 12.05$

The equations to solve are:

$0.25q + 0.10d = 12.05$

$d + q = 59$

Make d the subject in: $d + q = 59$

$d =59 - q$

Substitute $d =59 - q$ in $0.25q + 0.10d = 12.05$

$0.25q + 0.10(59 - q) = 12.05$

$0.25q + 5.9 - 0.10q = 12.05$

Collect like terms

$0.25q - 0.10q = 12.05 - 5.9$

$0.15q = 6.15$

Solve for q

$q=\frac{6.15}{0.15}$

$q=41$

Substitute $q=41$ in $d =59 - q$

$d = 59 - 41$

$d = 18$

So:

$Quarters = 41$

$Dimes = 18$

5 0

3 years ago

Some students reported how many pets they had. The dot plot shows the data collected: A dot plot is titled Students Pets and lab

hichkok12 [17]

Answer:B

Step-by-step explanation:I just know

4 0

3 years ago