the answer is they often contain biases :)
Answer:
d.) black-box testing
Explanation:
Software testing can be regarded as procedures/process engage in the verification of a system, it helps in detection of failure in the software, then after knowing the defect , then it can be corrected. Black Box Testing can be regarded as a type of software testing method whereby internal structure as well as design of the item under test is not known by one testing it. In this testing internal structure of code/ program is unknown when testing the software, it is very useful in checking functionality of a particular application. Some of the black box testing techniques commonly used are; Equivalence Partitioning, Cause effect graphing as well as Boundary value analysis. It should be noted that the purpose of black-box testing is to isolate the behavior of a given component of software.
Answer:
see explaination
Explanation:
#include<stdio.h>
/* Your solution goes here */
//Impllementation of SwapArrayEnds method
void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){
//Declare tempVariable as integer type
int tempVariable;
if(SORT_ARR_SIZE > 1){
tempVariable = sortArray[0];
sortArray[0] = sortArray[SORT_ARR_SIZE-1];
sortArray[SORT_ARR_SIZE-1] = tempVariable;
}
}
int main(void) {
const int SORT_ARR_SIZE = 4;
int sortArray[SORT_ARR_SIZE];
int i = 0;
sortArray[0] = 10;
sortArray[1] = 20;
sortArray[2] = 30;
sortArray[3] = 40;
SwapArrayEnds(sortArray, SORT_ARR_SIZE);
for (i = 0; i < SORT_ARR_SIZE; ++i) {
printf("%d ", sortArray[i]);
}
printf("\n");
return 0;
}
Please go to attachment for the program screenshot and output
Answer:
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Explanation:
Following are the program in c#
using System; // namespace
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Tasks
{
class Program
2 // program2
{
static void Main(string[] args) // Main function
{
double num = 958254.73789621; // variables
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Console.Read();
}
}
}
Output:
Format Double : 958254.737
Here we have declared a variable num of type double which store the value num=958254.73789621. To do format with the double number i used a syntax {0:n3}. This syntax {0:n3}is separated with :(colon) here 0 represent the value before the decimal point that is 958254 and n3 represent the value upto 3 decimal points. Hence this statement give the output with three digit after the decimal point .
A. because everyone basically has seen it..
