Answer:
def compute_pay(number_of_hours, rate_of_pay):
if number_of_hours > 40:
pay_for_week = (40*rate_of_pay)+((number_of_hours-40)*\
(rate_of_pay+rate_of_pay*0.5))
else:
pay_for_week = number_of_hours*rate_of_pay
if pay_for_week >= 375:
print("Paying %d by direct deposit" % pay_for_week)
else:
print("Paying %d by mailed check" % pay_for_week)
Explanation:
- We define the computer pay function that receives the number of hours worked in a week and the rate of pay
- From the test cases we deduce that if a worker works more than 40 hours a week an extra payment is given, you can calculated it as follow: (40 * rate_of_pay) + ((number_of_hours - 40) * (rate_of_pay + rate_of_pay * 0.5))
- If a worker works less than 40 hours the payment is calculated as follow: pay_for_week = number_of_hours * rate_of_pay
- If the pay for week is equal or greater than 375 we print a payment by direct deposit otherwise we print payment by mailed check
The answer to your question, is true
hope this helps :D
Answer:
Option d is the correct answer for the above question.
Explanation:
- The first loop of the program has a second loop and then the statement. In this scenario, the second loop executes for the value of the first loop and the statement executes for the value of the second loop.
- The first loop executes 4 times, Then the second loop or inner loop executes n times for the n iteration of the first loop, for example, 1 time for the first iteration of the first loop, 2 times for the second iteration of the first loop and so on.
- Then the inner loop executes (1+2+3+4) iteration which gives the result 10 iterations.
- The sum initial value is 0 and the "sum++", increase the value of the sum by 1.
- So the value of the sum becomes 10 after completing 10 iterations of the inner for loop.
- Hence the 10 will be the output. So the Option d is the correct answer while the other is not.
cool but kinda creepy ngl