Answer:
Step-by-step explanation:
The equation of a vertical line that passes through the point 
is given by;
The given point is 
.
This implies that,
is therefore the equation of the vertical line that passes through .
Problem 1)
Minor arc DG is 110 degrees because we double the inscribed angle (DHG) to get 2*55 = 110
Answer: 110 degrees
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Problem 2)
Central angle GDC is the same measure as arc GFC. The central angle cuts off this arc.
The arcs GEC and GFC both combine to form a full circle. There are no gaps or overlapping portions.
So they must add to 360 degrees
(arc GEC) + (arc GFC) = 360
(230) + (arc GFC) = 360
(230) + (arc GFC)-230 = 360-230
arc GCF = 130
Answer: 130 degrees
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Problem 3)
Similar to problem 1, we have another inscribed angle. ABC is the inscribed angle that cuts off minor arc AC
So by the inscribed angle theorem
arc AC = 2*(inscribed angle ABC)
3x+9 = 2*(3x-1.5)
Solve for x
3x+9 = 2*(3x-1.5)
3x+9 = 6x-3
9+3 = 6x-3x
12 = 3x
3x = 12
3x/3 = 12/3
x = 4
If x = 4, then
arc AC = 3x+9
arc AC = 3*4+9
arc AC = 21
Answer: 21 degrees
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Problem 4)
Since we have congruent chords, this means that the subtended arcs are congruent. In this case, the arcs in question are CO and HZ
So arc CO is congruent to arc HZ
Answer is choice D
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Problem 5)
We have a right triangle due to Thale's theorem
The angles 75 degrees and x degrees are complementary angles. They must add to 90
x+75 = 90
x+75-75 = 90-75
x = 15
Answer: Choice D) 15
Answer:
5
Step-by-step explanation:
Pythagoras theorem
Question: The number of animal births at a local zoo, displayed in five year intervals.
Answer: Histogram
Question: A comparison of the top songs by two schools.
Answer: double bar graph
Question: Top four ice-cream flavors chosen by the students, expressed in fractions.
Answer: Circle graph
Question: A change in the heart rates of two people over a period of an hour.
<span>Answer: Multiple line graph</span>
To find the mean, add all the numbers together and divide by the amount of numbers there is
89 + 92 + 97 + 81 + 96 = 455
455/5 = 91
91 is Andrew's mean score, and is your answer
hope this helps
