You can use the distance formula: d = sqrt((second x value - first x value)^2 + (second y value - first y value)^2):
answer : d = sqrt((3+2)^2+(6+6)^2) = 11.95826074 units
Answer:
(s-6)/r
option D
Step-by-step explanation:
The slope-intercept form a line is y=mx+b where m is the slope and b is the y-intercept.
Compare y=mx+b and y=cx+6, we see that m=c and c is the slope.
Now we are also given that (r,s) is on our line which means s=c(r)+6.
We need to solve this for c to put c in terms of r and s as desired.
s=cr+6
Subtract 6 on both sides:
s-6=cr
Divide both sides by r:
(s-6)/r=c
The slope in terms of r and s is:
(s-6)/r.
Answer: y=-2x-9
Step-by-step explanation:
If ANGL is a square, then NG and LG are adjacent sides.
Adjacent sides are perpendicular. [Each angle is 90°]
The equation of line NG is .
By comparing it to equation in slope intercept form y=mx+c ( where , m= slope , c=y-interecpt)
slope =
Let slope of LG be <em>n</em>, then
[Product of slopes of two perpendicular line =-1]
Equation of a line passes through (a,b) and have slope m is given by :-
Equation of LG :
[In intercept form]
It's c 18, because the diameter is the longest chord so it would be greater than 15.
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>