1) Sample space of the spinner={Green, Blue, Purple, Yellow, Red}=5
2) Sample space of the cards={Red, Yellow, Blue, Pink }=4
1) P(spinner stops at purple) = 1/5
2) P(pink card selected) = 1/4
1) AND 2) are conditional probabilities:
P(spinner stops at purple ∩ pink card selected ) = (1/5)(1/4) = 1/20 =0.05
Answer:
-9x +6
Step-by-step explanation:
The usual statement of the distributive property tells you how this works:
a(b + c) = ab + ac
-1(9x -6) = (-1)(9x) +(-1)(-6) = -9x +6
Answer:
<u>Step-by-step explanation:</u>
a) Number of arrangements in which bride is not next to the groom
= Total number of arrangements - Number of arrangements in which bride and groom are next to each other
= 10! - 2*9!
= 2903040
b) Number of arrangements such that groom is not at the leftmost position
= Total number of arrangements - Number of arrangements with groom at leftmost position
= 10! - 9!
= 3265920
c) Number of ways such that groom is not at one end
= Total number of arrangements - Number of arrangements with groom at one end
= 10! - 2*9!
= 2903040
