Answer:
a) 81π in³
b) 27 in³
c) divide the volume of the slice of cake by the volume of the whole cake
d) 10.6%
e) see explanation
Step-by-step explanation:
<h3><u>Part (a)</u></h3>
The cake can be modeled as a <u>cylinder </u>with:
- diameter = 9 in
- height = 4 in



<h3><u>Part (b)</u></h3>

If each slice of cake has an arc length of 3 in, then the volume of each slice is 3/9π of the entire volume of the cake.

<h3><u>Part (c)</u></h3>
The volume of each slice of cake is 27 in³.
The volume of the whole cake is 81π in³.
To calculate the probability that the first slice of cake will have the marble, divide the volume of a slice by the volume of the whole cake:

<h3><u>Part (d)</u></h3>
Probability is approximately 10.6% (see above for calculation)
<h3><u>Part (e)</u></h3>
If the four slices of cake are cut and passed out <em>before </em>anyone eats or looks for the marble, the probability of getting the marble is the same for everyone. If one slice of cake is cut and checked for the marble before the next slice is cut, the probability will increase as the volume of the entire cake decreases, <u>until the marble is found</u>. So it depends upon how the cake is cut and distributed as to whether Hattie's strategy makes sense.
Answer:
all work is shown/pictured
We know that
the scale is <span>is 1/2 inch = 4 feet
using a graph tool
</span><span>the approximate measurements in the drawing are
</span>5 cm x 4 cm
convert to in
5/2.54--------> 1.97 in
4/2.54------> 1.57 in
convert drawing to actual
if 0.5 in---------> 4 ft
1.97in-------> X
X=1.97*4/0.5------> X=15.76 ft
if 0.5 in---------> 4 ft
1.57 in-------> X
X=1.57*4/0.5------> X=12.56 ft
<span>the approximate area of Quinto's bedroom is 12.56*15.76=197.95 ft</span>²
the answer is
the option C)192 ft²
Answer:
Correct option: (a)
Step-by-step explanation:
A confidence interval is an interval estimate of the parameter value.
A (1 - <em>α</em>)% confidence interval implies that the confidence interval has a (1 - <em>α</em>)% probability of consisting the true parameter value.
OR
If 100 such confidence intervals are made then (1 - <em>α</em>) of these intervals would consist the true parameter value.
The 92% confidence interval for the mean annual phone charge of all Vopstra customers is:

This confidence interval implies that true mean annual phone charge of all Vopstra customers is contained in the interval ($405, $535) with 0.92 probability.
Thus, the correct option is (a).