Answer:
According to theorem 7.5
Π ABB'A' ≅ Π DEE'D'
therefore by transitivity of equivalence it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides
Step-by-step explanation:
To prove that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides :
Assume: б(Δ ABC ) = б(Δ DEF ) and also AB ≅ DE
let Π ABB'A' and DEE'D' be taken as the saccheri quadrilaterals that corresponds to Δ ABC and Δ DEF respectively
Following the Lemma above; б(Π ABB'A' ) = б( Π DEE'D' ) given that
AB = summit of ABB'A' and DE = summit of DEE'D' also AB ≅ DE
According to theorem 7.5
Π ABB'A' ≅ Π DEE'D'
therefore by transitivity of equivalence it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides
Amir at 10 strawberries
Explanation:
Less= subtract
15-5=10
Answer:
(1, 3)
Step-by-step explanation:
Answer:
86
Step-by-step explanation:
Answer:
look at my explanation
Step-by-step explanation:
Find the area of two sides (Length*Height)*2 sides. Find the area of adjacent sides (Width*Height)*2 sides. Find the area of ends (Length*Width)*2 ends. Add the three areas together to find the surface area
