If a quadrilateral is a parallelogram, it has diagonals which form 2 congruent triangles. Use the following, to PROVE a parallelogram: DEFINITION: A parallelogram is a quadrilateral with both pairs of opposite sides parallel.
The mode would be 17, it’s the number that appears the most. I’m not rewriting it though
First thing you should do is <span>Distribute...
</span>=(2)(2)+(2)(−x)+−3x
=4+−2x+−3x
<span>Next is to Combine like terms..
</span>=4+−2x+−3x
=(−2x+−3x)+(4)
<span>Answer..
</span>=−5x+4
Good luck with your studies~ ^//^
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PLEASE HELP MEEEEEEEE IM BEGGING
Answer:
Step-by-step explanation:
To start calculating, we first need to make some proof.
Firstly, since AB = AC, we know that ΔABC is isosceles, which means that ∠ABC = ∠ACB.
Now, looking only to ΔBDE and ΔCDF, we can see that they are similar, because the two of its angles are congruent:
∠BED=∠CFD
∠DBE=∠DCF
To make it easier to visualize which are the corresponding vertexes, we can draw them like this:
And we need to remember that BC is 24, so:
BD+CD=24
Since the triangles are similar, their corresponding sides have constant ratio, which we can calculate from the corresponding sides DE and CF:

This ratio is the same for the other corresponding sides, so we can apply that for BD and CD:

Thus, the measure of CF is approximately 13, alternative D.