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Blababa [14]
3 years ago
15

Evaluate the following expressions for x = 2.

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

1. -9.2(4-2)= -18.4

2. -36.8+9.2(2)= -18.4

Step-by-step explanation:

just plug in 2 in stead of x

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Which of the following points is shown in the graph below?
djverab [1.8K]

Answer:

Step-by-step explanation:

Comment

  • Only the x is minus. You know this because if you rotate the x axis 90 degrees clockwise, the plus axis will be on your right and the minus part of the axis on your left.
  • The other 2 (y and z) are positive.
  • All answers give - 4 in their choices. You are not helped much by -4
  • y is on your left right now. That is the plus direction so y = 5
  • z is 6 units up, so it is positive.

Answer (-4,5,6)

B

4 0
2 years ago
Show that the sum of the first 2n natural numbers is n(2n+1)
Leokris [45]

Answer:

This sum is the sum of an arithmetic sequence.  There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.

A nice approach for this sequence is the following.  Notice  that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.

There are n of these pairs.  So the desired sum is n x (first number + last number).   But the first number is 1 and the last on is 2n.   Thus the desired sum is n(1 + 2n).

Hope this helps!!

Mark Brainleast!!!!!!!!!!!

7 0
2 years ago
Read 2 more answers
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
=
ivann1987 [24]

9514 1404 393

Answer:

  • large: 55 lb
  • small: 30 lb

Step-by-step explanation:

Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...

  x + y = 85 . . . . . combined weight of a large and small box

  70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes

We can subtract 50 times the first equation from the second to find the weight of a large box.

  (70x +50y) -50(x +y) = (5350) -50(85)

  20x = 1100 . . . . simplify

  x = 55 . . . . . . . divide by 20

Using this in the first equation, we can find the weight of a small box.

  55 +y = 85

  y = 30 . . . . . . . subtract 55

A large box weighs 55 pounds; a small box weighs 30 pounds.

4 0
3 years ago
Please Solve This Problem For Me<br><br> x^2 + 5^2 = 7^2<br><br> (^2 Means Squared)
Triss [41]
X^2+5^2=7^2
x^2+25=49
(49-25)
x^2=24
sqrt(24)=4.89897948557
7 0
3 years ago
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