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3 years ago

Can someone help me with this question please

Mathematics

1 answer:

Rama09 [41]3 years ago

3 0

Answer B would be the best answer because it states how the prices differ and the 1 Liter bottle is able to go into the 2 liter bottle almost two times. Answer A could also be correct but B is more descriptive.

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What is the best name for angle Y

Blizzard [7]

This question doesnt make sense u need to attach a picture

5 0

3 years ago

Usain Bolt ran miles in of an hour. A domestic cat runs miles in 9 4 153 1 3 4 3 8 1 of an hour. Would Usain Bolt or a domestic

ratelena [41]

He is 30th place behind white tail deer, warthog, grizzly bear, and house cat

8 0

3 years ago

Read 2 more answers

The graph of function f is shown above. if g(x)=x^2/f(x) what is the value of g'(1)?

Alla [95]

Answer:

Step-by-step explanation:

Find the equation of the segment going from (0,-5) to (3,7)

y intercept = -5

Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4

equation: y = 4x - 5

g(x) = x^2 / f(x)

f(x)= (4x - 5)

g(x) = x^2 / (4x - 5)

g'(x) = x^2 * (4x - 5)^-1

g'(x) = 2x*(4x - 5)^-1 + (-1) *4* x^2 (4x - 5)^-2

I will leave that monster the way it is and just find g'(1)

g'(1) = 2(1) * (4(1) - 5)^-1 + (-1) (1)^2 *4* (4(1) - 5)^-2

g'(1) = 2(1) * (-1)^-1 + (-1) (1)^2 *4 * (-1)^2

g'(1) = -2 + (-1) (1)^2 (4)

g'(1) = - 2 + (-1) (1)^2 (4)

g'(1) = - 2 - 4

g'(1) = - 6

7 0

2 years ago

If P(not A) = 0.18 and P(A and B) = 0.44, what is P(B given A)?

pickupchik [31]

p(not A)=0.18

p(A&B)= 0.44

A= 0.44- 0.18

= 0.26

P(B given A)= 0.26+0.18+0.44

=0.7

3 0

3 years ago

An individual saves $5000 in a bank account at the beginning of each year for 10 years.

frozen [14]

Answer:

a) Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually is $5849.5

Step-by-step explanation:

Principal Amount P = 5000

Time t = 10 years

Annual interest i = 8% = 0.08

We need to find amount saved if interest is compounded a) annually b) semi-annually

a) Amount saved if the interest is compounded annually

If interest compounded annually, n= 1

Using Formula: $A=P(1+\frac{r}{n})^{nt}$

Putting values:

$A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{1})^{1*2}\\A=5000(1+0.08)^2\\A=5000(1.08)^2\\A=5000(1.1664)\\A=5832$

So, Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually

If interest compounded semi-annually, n= 2

Using Formula: $A=P(1+\frac{r}{n})^{nt}$

Putting values:

$A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{2})^{2*2}\\A=5000(1+0.04)^4\\A=5000(1.04)^4\\A=5000(1.1699)\\A=5849.5$

So, Amount saved if the interest is compounded semi-annually is $5849.5

4 0

3 years ago