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oksano4ka [1.4K]
1 year ago
13

At the BlueBird Cinema you can select

Mathematics
1 answer:
lara31 [8.8K]1 year ago
6 0

Using the Fundamental Counting Theorem, there are 400 ways to see a movie, have a drink and choose a type of candy.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

Considering the number of movies, drinks and candies, the parameters are given as follows:

n_1 = 10, n_2 = 5, n_3 = 8

Hence the number of ways is given by:

N = 10 x 5 x 8 = 400.

There are 400 ways to see a movie, have a drink and choose a type of candy.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

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Randy filled 48 pint jars to the top with jelly. How many gallons of jelly did Randy make it? Explain.
cestrela7 [59]

Answer:

24

Step-by-step explanation:

The conversion is half (1/2) Every 1 quart is two pints. If Randy had 48 pints of jelly, we simply divide 48 by 2...


48/2=24

3 0
3 years ago
I don’t really understand how to do this… summer brain
avanturin [10]

The corresponding angle to angle 1 is angle 11.

<h3>How to depict the angles?</h3>

It should be noted that corresponding angles are the angles that occupy the same relative position at each intersection.

The alternate exterior angle to 12 is angle 4.

The alternate interior angle to angle 6 will be angle 9.

The vertical angle to angle 4 is angle 2. They are angles that are opposite each other when two lines cross.

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4 0
2 years ago
Could you do this for me
Margaret [11]
16.. (the rest of the number)
——- * 100
21….(the rest of the number)

6 0
2 years ago
Here is the sample space for three tosses of a coin.
BARSIC [14]
Assuming the coin is fair, the probability of the coin toss resulting in H is p=\dfrac12. So the probability of getting two Hs, in any order, is

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6 0
3 years ago
Read 2 more answers
In a survey of 100 outpatients who reported at a hospital one day,it was found that 70 complained of fever, 50 had stomach troub
Verdich [7]
6 patients had all three complaints.
We can't subtract 44 from 30.
we can subtract that from from 50 which leaves us with 6 patients that can have the third complaint as well.
We can also subtract 44 from 70 but the remaining number exceeds the number of patients with stomach ache.
so it leaves us with 6.
Revising:
So according to the survey
All 44 have exactly two complaints
30 patients were injured
50 had stomach ache
70 had fever
1. 30 is less than 44 so that leaves it outside
2. 50 is greater than 44 so we subtract 44 from 50. 6 patients are those who can have all three complaints.
3. 70 is also greater than 44 so we subtract 44 from 70. 26 patients are left behind.
The number of patients can't be higher than 6 because that is the number of patients that have stomach ache and can also have the other two complaints. Hence 6 patients have all three complaints.
6 0
3 years ago
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