HELP ME ASAP PLEASE

The value of computer decreases with its age until it is worth nothing a computer that was purchases new for 0 years is worth 22

Georgia [21]

Answer:

$V(x) = -\frac{340}{3}x +2220$

$V(8) = 1313.3$

Step-by-step explanation:

Given

Let x represent years and V represents the value.

So, we have:

$(x_1,v_1) = (0,2220)$

$(x_2,v_2) = (6,1540)$

Solving (a): The linear function

First, we calculate the slope (m)

$m = \frac{v_2 - v_1}{x_2 - x_1}$

This gives:

$m = \frac{1540-2220}{6-0}$

$m = \frac{-680}{6}$

$m = -\frac{340}{3}$

The linear function is calculated using:

$v - v_2 = m(x - x_2)$

Where:

$(x_2,v_2) = (6,1540)$

$m = -\frac{340}{3}$

So, we have:

$v - 1540 = -\frac{340}{3}(x - 6)$

Open bracket

$v - 1540 = -\frac{340}{3}x +\frac{340}{3}* 6$

$v - 1540 = -\frac{340}{3}x +680$

Make v the subject

$v = -\frac{340}{3}x +680+1540$

$v = -\frac{340}{3}x +2220$

So, the function is:

$V(x) = -\frac{340}{3}x +2220$

Solving (b): When x = 8

Substitute 8 for x in $V(x) = -\frac{340}{3}x +2220$

$V(8) = -\frac{340}{3}*8 +2220$

$V(8) = -\frac{340*8}{3} +2220$

$V(8) = -\frac{2720}{3} +2220$

Take LCM

$V(8) = \frac{-2720+2220*3}{3}$

$V(8) = \frac{-2720+6660}{3}$

$V(8) = \frac{3940}{3}$

$V(8) = 1313.3$

<em>Hence, its value after 8 years is 1313.3</em>

3 0

3 years ago

Choose all the polynomials that are in standard form?

Allisa [31]

<h3>2 Answers: Choice B and Choice D</h3>

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Explanation:

Standard form will always have the largest exponents listed first on the left side. Then as you move to the right, the exponents will decrease. Choice B shows this with the exponents counting down (3,2). Choice D is a similar story with the exponents counting down (9,2,1,0). Think of -6x as -6x^1, and also think of the 10 as 10x^0.

Something like choice A is a non-answer because the term with the largest exponent 3 is buried in the middle, and not at the left side. The exponents are not in decreasing order. Choice C can be ruled out for similar reasons.

Side note: the largest exponent is the degree of the polynomial. This only applies to single variable polynomials.

6 0

3 years ago

Read 2 more answers

Problem PageQuestion The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate paramet

asambeis [7]

Answer:

Step-by-step explanation:

<u>Exponential Model</u>

The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.

The model can be expressed as

$M=M_oe^{kt}$

In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.

The value of k is not precisely given in the question, we are assuming $k=-0.2$