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3 years ago

HELP ME ASAP PLEASE

Mathematics

1 answer:

vfiekz [6]3 years ago

5 0

Answer:

144.44

Step-by-step explanation:

C = 2 x π x r . C = 2 x 3.14 x 23 = 144.44

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snow_tiger [21]

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3 years ago

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choli [55]

Answer:

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An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t

alina1380 [7]

Answer:

Step-by-step explanation:

Given

Height of building is $h=110\ ft$

Initial upward velocity $u=23\ ft/s$

height of object is given by

$z(t)=ut+\frac{1}{2}gt^2$

but building is already at a height of 110 ft so z(t) must be given by

$Z(t)=ut+\frac{1}{2}(-g)t^2+110$

$Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2$

$Z(t)=-16t^2+23t+110$

Time when it hits is given by when Z(t)=0[/tex]

$-16t^2+23t+110=0$

$t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}$

$t=\frac{-23\pm 87}{-32}$

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3 years ago

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Vladimir [108]

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2 years ago

Read 2 more answers

PLEASEEE HELP ME WITH THIS!!!

andreev551 [17]

Answer:

m∠H = 10°

Step-by-step explanation:

ΔFGH is an isosceles triangle. I made a diagram, so m∠F ≅ m∠H by B.A.T(base angle theorem). This is because an isosceles triangle have to congruent sides and angles.

Diagram is attached:

-Chetan K

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3 years ago