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olga_2 [115]
2 years ago
9

Tìm kiếm x y z x-1/y =1 y-1/z =1 z-1/x =1

Mathematics
1 answer:
const2013 [10]2 years ago
3 0

<em>y</em> - 1/<em>z</em> = 1   ==>   <em>y</em> = 1 + 1/<em>z</em>

<em>z</em> - 1/<em>x</em> = 1   ==>   <em>z</em> = 1 + 1/<em>x</em>

==>   <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)

<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1

==>   2<em>x</em> ² - 1 = 2<em>x</em> + 1

==>   2<em>x</em> ² - 2<em>x</em> - 2 = 0

==>   <em>x</em> ² - <em>x</em> - 1 = 0

==>   <em>x</em> = (1 ± √5)/2

If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.

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