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snow_lady [41]
3 years ago
15

Write 3.5 times 4 using words ?​

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0

Answer:

three point five multiplied by four

Step-by-step explanation:

Lyrx [107]3 years ago
5 0

Answer:

three point five multiplied by four

(this is just in case ou need to write the answer to the problem too)

equals fourteen

Step-by-step explanation:

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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 380 babies were​ born, a
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Answer:

The 99​% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

In the study 380 babies were​ born, and 342 of them were girls.

This means that n = 380, \pi = \frac{342}{380} = 0.9

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.9 - 2.575\sqrt{\frac{0.9*0.1}{380}} = 0.8604

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.9 + 2.575\sqrt{\frac{0.9*0.1}{380}} = 0.9396

As percentages:

0.8604*100% = 86.04%.

0.9396*100% = 93.96%.

The 99​% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.

4 0
3 years ago
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