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3 years ago

Describe 2 ways you could evaluate 37% of the sum of 27 3/5 and 15/9

1 answer:

3 0

First way is create an equation like this:
$0.37(27 \frac{3}{5}+ \frac{15}{9})$
and calculating it.
Second way is to find 37% of each number and then add it
$0.37*27 \frac{3}{5}$ + $0.37* \frac{15}{9}$
In both cases the result is 10.829

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You want to give your friend a soccer ball for a gift. The soccer ball has a

Ede4ka [16]

Answer:

volume of cube share box = 67.92 inch²

Step-by-step explanation:

given data

soccer ball volume = 85.3π cubic inches

solution

we know that ball will fit inside the box when box length will be equal to diameter of ball

and here soccer ball volume will be express as

soccer ball volume = $\frac{4}{3}\times \pi \times r^3$ .................1

85.3π = $\frac{4}{3}\times \pi \times r^3$

solve it we get

r³ = 69.9765

r = 4.12 inch

so diameter = 2 × 4.12 = 8.24 inch

diameter = length of box side

volume of cube share box = a²

volume of cube share box = 8.24²

volume of cube share box = 67.92 inch²

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3 years ago

Simplify 2y-6x+5+4y<br> What is the answer?

Misha Larkins [42]

Answer:

Answer = −6x+6y+5

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2 years ago

If the equation looks like this: y = 2x +6 it is in what form?

Nata [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The numbers x, y, z and w have an average equal to 25. The average of

murzikaleks [220]

Answer:

look at the picture i sent

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2 years ago

1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit

Stels [109]

$\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}$

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

$P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})$

"Chocolate" has the marginal distribution given by the second column, with a total probability of $P(\text{chocolate})=0.35$ . Similarly, "Adults" has the marginal distribution described by the third row, so that $P(\text{adults})=0.60$ . Then

$P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21$

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with $P(\text{chocolate}\cap\text{adults})=0.21$ .

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;

$P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14$
$P(\text{children}\cap\text{chocolate})=0.14$

c. Yes;

$P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26$
$P(\text{vanilla}\cap\text{children})=0.26$

5 0

3 years ago