3 years ago

Anyone please help me

Mathematics

1 answer:

o-na [289]3 years ago

4 0

Answer: can’t help

Step-by-step explanation:

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Answer:

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Remember that anything to the 0th power is going to be 1 in terms of exponent rules!

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FinnZ [79.3K]

Answer:

Given expression:

$\dfrac{14a^4b^6c^{-10}}{8a^{-2}b^3c^{-5}}$

Separate the variables:

$\implies \dfrac{14}{8} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}$

Reduce the first fraction:

$\implies \dfrac{7}{4} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}$

$\textsf{Apply Division Property of Exponents rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies \dfrac{7}{4} \cdot a^{4-(-2)} \cdot b^{6-3} \cdot c^{-10-(-5)}$

$\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot c^{-5}$

$\textsf{Apply Negative Property of Exponents rule} \quad a^{-n}=\dfrac{1}{a^n}$

$\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot \dfrac{1}{c^5}$

Therefore:

$\implies \dfrac{7a^6b^3}{4c^5}$

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