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2 years ago

Which of the equations below shows the relationship in the table?

Mathematics

1 answer:

poizon [28]2 years ago

7 0

Answer: y=15/x

For this problem you need to use trial and error.

For the first equation, 15-14 does equal 1, but 5-14 doesn’t equal 3. For the second equation, 15x15 doesn’t equal 1. For the third equation, 15+2 doesn’t equal 1. For the last equation, 15/15 is 1, 15/5 is 3, and so on. So, the last equation shows the relationship in the table.

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Jay ate 2/3 of a pizza. Dan ate 4 times the amount of jay ate . How much did dan eat

erica [24]

Answer:

Dan eat $2\frac{2}{3}$ pizzas

Step-by-step explanation:

Let

x-----> amount of pizza Jay ate

y-----> amount of pizza Dan ate

we know that

$x=\frac{2}{3}$ ----> equation A

$y=4x$ -----> equation B

substitute equation A in the equation B and solve for y

$y=4(\frac{2}{3})=\frac{8}{3}$

Convert to mixed number

$\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}$

8 0

3 years ago

What is the area of the parallelogram? ? sq ft

jenyasd209 [6]

parallelogram formula is b*h because u can just move a part of the triangle to make it become a rectangle or square. so square/rectangle's formula is the exactly same.

answer:63

hope this helps :D

7 0

4 years ago

Read 2 more answers

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!