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Answer:
Attached diagram A'B'C'D'
Step-by-step explanation:
Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.
We see that scale factor is less than 1 which means it shrinks the image to a smaller one.
To draw a scaled copy, we need to find the lengths of its sides.
To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.
Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.
So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.
Answer:
The equation of the circular wheel is .
Step-by-step explanation:
Given :
Radius of Ferris wheel r = 70 feet.
The distance between the wheel and the ground = 4 feet.
Also, the rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.
So the x coordinate of center of wheel must be 0 , and y coordinate = 70 + 4 = 74
Thus, Coordinates of center = (0,74)
The equation of circle is given by :-
Now center (h,k) = (0,74) and r = 70 , we get
Hence, the equation of the circular wheel is .
We know that .
Using this rule,
.
We also know that .
Using this rule,
Now we know that so,
.
Hope this helps :)