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zzz [600]
3 years ago
13

Me+You=? wanna test our equation? ;3

Mathematics
2 answers:
Montano1993 [528]3 years ago
7 0

Answer:

Okay, that was smooth-

Step-by-step explanation:

Use that when you ask someone out.

Vika [28.1K]3 years ago
5 0
Hahaha anyway thanks for the free point
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Y=2x-pq rearrange the formula to make x the subject
professor190 [17]
Y=2x-pq
2x=y+pq
x=(y+pq) / 2

7 0
4 years ago
What is the factored form of the expression. (2n^2 + 5n + 3) (4n - 5)
7nadin3 [17]

So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>

So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

(2n^2 + 2n + 3n + 3)(4n - 5)

Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

(2n(n+1)+3(n+1))(4n-5)

Now we can rewrite this expression as<u> (2n+3)(n+1)(4n-5) , which is your final answer.</u>

7 0
3 years ago
Reason is the value of the first 5 ten times as great as the value of the second 5 in 5045?
vovikov84 [41]

It is not. In the decimal system each column to the right is valued at powers of ten starting at zero and increasing as you move to the left...in a four digit number...the columns are valued at...

10^3, 10^2, 10^1, 10^0 which corresponds to...

1000, 1000, 10, 1 in this case the first digit is equal to

5(1000)=5000 the value of the last digit is 5(1)=5

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Hope this helps!

4 0
3 years ago
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri
zalisa [80]

Answer:

a

 P(\= X \ge 51 ) =0.0062

b

P(\= X \ge 51 ) = 0

Step-by-step explanation:

From the question we are told that

The mean value is \mu = 50

The standard deviation is  \sigma = 1.2

Considering question a

The sample size is  n = 9

Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{9} }

=>  \sigma_x = 0.4

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

      P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}}  \ge \frac{51 - 50 }{0.4 } )

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

     P(\= X \ge 51 ) = P( Z  \ge 2.5 )

=>   P(\= X \ge 51 ) =1-  P( Z  < 2.5 )

From the z table  the area under the normal curve to the left corresponding to  2.5  is

    P( Z  < 2.5 ) = 0.99379

=> P(\= X \ge 51 ) =1-0.99379

=> P(\= X \ge 51 ) =0.0062

Considering question b

The sample size is  n = 40

   Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{40} }

=>  \sigma_x = 0.1897

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as  

       P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x}  \ge \frac{51 - 50 }{0.1897 } )

=> P(\= X \ge 51 ) = P(Z  \ge 5.2715  )

=>  P(\= X \ge 51 ) = 1- P(Z < 5.2715  )

From the z table  the area under the normal curve to the left corresponding to  5.2715 and

=>  P(Z < 5.2715  ) = 1

So

   P(\= X \ge 51 ) = 1- 1

=> P(\= X \ge 51 ) = 0

5 0
3 years ago
I worked on the project until it was completed.
wolverine [178]
The subordinate clause would be “until is was completed”
3 0
3 years ago
Read 2 more answers
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