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3 years ago

If You write all numbers from 30 to 65 including 30 and 65 how many times would you write the digit 4?

Mathematics

1 answer:

BaLLatris [955]3 years ago

6 0

Answer:

We write 4 times 4 because it includes 34,44,54,64in the data.

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Felipe's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A costs Felipe $4.55 per lb. Type B costs $5.7

RUDIKE [14]

Answer:

Type A coffee in lbs = 97 lbs

Step-by-step explanation:

Type a = 4.55/lbs = x

type b = 5.70/lbs = y

Total in lbs = 147lbs

total in sales = 726.50

First,

x + y = 147 lbs -------------------equ 1

4.55x + 5.70y = lbs ------------ equ 2

<em>Multiply equ 1 by 4.55</em>

4.55x + 4.55y = 668.85 -------------equ 3

4.55x + 5.70y = 726.50 ------------equ 4

<em>Subtracting equ 3 from equ 4</em>

1.15y = 57.65

y = 50

<em>Substituting y = 50 into equ 1</em>

x + 50 = 147

x = 97

7 0

3 years ago

a science quiz has eight multiple choice questions with five choices for each. Find the total number of ways to answer the quest

almond37 [142]

Answer:

390625

Step-by-step explanation:

The questions are all independent -- the answer on one question does not limit the number of possible answers on another question.

The quiz has 5 choices for each question, so there are

$5\times5\times5\times5\times5\times5\times5\times5$ ways to answer the quiz questions.

Notice that this could be written $5^8$ . You could say that the number of ways to answer the questions is

$number \, of \, choices^{number \, of \, questions}$

Use a calculator to find $5^8$

8 0

3 years ago

a box contains 20 red, 10 blue and 30 yellow beads. what is the probability of a bead drawn at random being yellow or blue?

dexar [7]

Answer:

2/3

Step-by-step explanation:

1. add all the beads up together:

20+10+30= 60

2. add the blue and yellow beads up:

10+30= 40

3. put 40 over 60

40/60 which equals 2/3

4. the final answer:

2/3

5 0

3 years ago

8. The Last Supper

Salsk061 [2.6K]

The number of possible seats is an illustration of permutation

There are 1728 possible sitting arrangements

<h3>How to determine the number of seats</h3>

From the question, we have the following highlights:

Chris can only take 1 seat (i.e. the central seat)
Jo can take 2 seats (i.e. the seats adjacent the central seat)
Alex, Barb and Dave can take 3! number of seats
Eddie, Fred, and Gareth can take 3! number of seats on the right of Chris.
The remaining 4 adults do not have preference, then they can seat in 4! ways

So, the number of sitting arrangement is:

$n = 1 * 2 * 3! * 3! * 4!$

Evaluate the product

$n = 1728$

Hence, there are 1728 possible sitting arrangements