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Yuki888 [10]
3 years ago
14

The area of a rectangular patio is 27 5 8 square meters. The width of the patio is 3 1 4 meters. What is the length? Enter your

answer as a mixed number in simplest form.
Mathematics
1 answer:
DedPeter [7]3 years ago
8 0

Answer:

Step-by-step explanation:

L and W are length and width, respectively.

W = 3¼ = 13/4

Area = LW = 27⅝ = 221/8 m²

L = area/W = (221/8)/(13/4) = (221/8)(4/13) + 221/26 = 17/2 = 8½ m

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Describe the difference between an angle with a positive measure and an angle with a negative measure.
Lana71 [14]

Answer:

negative is rotating counter clockwise and positive is straight

Step-by-step explanation:

positive 180 degresse rotation

7 0
3 years ago
If you need 192 beads to make a necklace and bracelet and it takes 5 times more beads to make necklace than bracelet. How many b
Rasek [7]
192 = total beads

necklace + bracelet = 192

Let x equal the number of beads 

bracelet = 5x
necklace = x

5x + x = 192 

6x = 192

x = 32

It takes 32 beads to make a necklace

3 0
3 years ago
Is 1 Greater then -4
Nikitich [7]

Answer:

Yes 1 is greater than -4

Step-by-step explanation:

5 0
3 years ago
When twice a certain number is added to 7,the result is less than 17.what is the number.​
EleoNora [17]

Answer: 2?

Step-by-step explanation:

7 0
3 years ago
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
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