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2 years ago

Help, in geometry please?Thank you!

Mathematics

1 answer:

Svet_ta [14]2 years ago

7 0

1) Draw the triangles JKL and J'K'L' in a same coordinate system.

When I did that, I realize the if you translate the triangle JKL 1 unit left and then you reflects the image across the x-axys you get the you get the triangle J'K'L'.

So, select the boxes in that same order:

1) translation 1 unit left

2) reflection across the x - axis.

2) The answer ot the second question is line r.

That is called the line of reflection because if you reflect the figures through it you will have the same figure.

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Please answer correctly show work and no links thanks!

OLEGan [10]

Answer: I think it is 12.375 ft

Step-by-step explanation: I multiplied the two numbers together. I’m not sure if this is right! Sorry if it isn’t!

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2 years ago

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Each of 5 gift bags contains X pencils.Tyler add 3 more pencil to each bag.together the gift pack contain 20 pencils.

noname [10]

Answer:

4.6

Step-by-step explanation:

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2 years ago

A bag of skittles only contain red pieces,yellow,and orange .If there are 6 red 8 yellow 4 orange pieces, what is the ratio of r

Trava [24]

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Step-by-step explanation:

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2 years ago

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"Lashonda swam 4 kilometers against the current in the same amount of time it took her to swim 16 kilometers with the current. T

Naddika [18.5K]

Answer:

5 km/h

Step-by-step explanation:

In this problem, Lashonda swam 4 km against the current. So the distance covered in this case is

$d_1=4 km$

Calling $v$ the velocity of Lahonda without the current, and $c$ the velocity of the current, in this situation Lahonda's velocity is

$v-c$

So we can write:

$t_1=\frac{d_1}{v-c}$

where $t_1$ is the time taken to cover the distance.

When Lashonda swims with the current, her velocity is

$v+c$

So we can write

$t_2=\frac{d_2}{v+c}$

where

$d_2=16 km$ is the distance covered in this case, and $t_2$ the time taken.

The velocity of the current is

$c=3 km/h$

Since Lashonad takes the same time to cover the two distances,

$t_1=t_2$

So we can write

$\frac{d_1}{v-c}=\frac{d_2}{v+c}$

And solving for v, we find Lashonda's velocity without the current:

$d_1(v+c)=d_2(v-c)\\d_1 v+d_1c = d_2v-d_2c\\v(d_2-d_1)=c(d_1+d_2)\\v=\frac{d_2+d_2}{d_2-d_1}c=\frac{16+4}{16-4}(3)=5 km/h$

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3 years ago

In a plane, line N is parallel to line O, line O is parallel to P, and line L is perpendicular to line N. Which must be true? N.

Leni [432]

The <u>correct answer</u> is:

Line L must be perpendicular to both line O and line P as well.

Explanation:

Since N, O and P are all parallel, any line that intersects N will intersect O and P at the same angle. Since L is perpendicular to N, intersecting at a right angle, this means it must be perpendicular to O and P also.

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3 years ago