Question

Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°​

Answer 1

Answer:

x = 71°

Option B is correct answer.

Step-by-step explanation:

We need to find for what value of x is $sin\: x = cos 19^{\circ}$, where 0°< x < 90°?

Solving:

$sin\: x = cos\: 19^{\circ}\\Finding \:cos\: 19^{\circ}=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^{-1}(0.94551)\\x=71^{\circ}$

So, we get x = 71°

Option B is correct answer.