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iragen [17]
3 years ago
12

Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°​

Mathematics
1 answer:
Lerok [7]3 years ago
5 0

Answer:

x = 71°

Option B is correct answer.

Step-by-step explanation:

We need to find for what value of x is sin\: x = cos 19^{\circ}, where 0°< x < 90°?

Solving:

sin\: x = cos\: 19^{\circ}\\Finding \:cos\: 19^{\circ}=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^{-1}(0.94551)\\x=71^{\circ}

So, we get x = 71°

Option B is correct answer.

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