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katen-ka-za [31]
3 years ago
7

*forgets how to do this*

Mathematics
2 answers:
hammer [34]3 years ago
8 0

Answer:

-12

Step-by-step explanation:

-8-(-12= -8+12

well, 12-8=4, so -8+12=4

Aleksandr-060686 [28]3 years ago
5 0

Answer:

4

Step-by-step explanation:

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Stolb23 [73]

Answer:

No solution

Step-by-step explanation:

There are no values of x that make the equation true; hence making it have no solution.

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Evaluate the radical.<br> (Look at the photo)<br> Enter your answer in the box.
faltersainse [42]

Answer:

3

Step-by-step explanation:

This is a cube root so think what times what times what is 27?

3 x 3 x 3 = 27 so the answer is 3

Same problem explained

https://www.mathsisfun.com/numbers/cube-root.html  < in detail.

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3 years ago
I need help with this
Alex73 [517]

Answer: the third one

Step-by-step explanation:

3 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
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