Step-by-step explanation:
as the graphic shows, we are dealing with a special rhombus : a square.
this is proven by the fact that the angle on one side of the diagonal at the corner is 45°. so, the other side must be 45° too, and so we have 90° angles at the corners.
what is not clear to me is : what is 6 cm long ? a half-diameter, or the whole diameter ?
I assume the half-diameter.
what the graphic is trying to suggest is that we have 4 little right-angled triangles that are also isoceles triangles (their legs are equally long).
every leg is 6 cm long (based on my assumption above).
because they are right-angled, the area of each of these little triangles is leg×leg/2
6×6/2 = 18 cm²
we have 4 triangles, so the total area is
4×18 = 72 cm²
if 6 cm stands for the whole diagonal after all, then the only change is the length of the legs, which would be then 6/2 = 3 cm.
then we would have
3×3/2 = 4.5 cm² for a single triangle
and
4×4.5 = 18 cm² for the whole area.
Answer:
1) n + 7 = 20
2) x + 7 = 14
3) x + n = 21
4) 11 +n = 19
5) x - 17 = 14
6) 12 - x = 8
7) x - 4 = 30
8) 8x = 56
9) 1/2n = 18
10) 2(n > 4) = 12
11) 4n = 12
12) n + 2 = 14
13) n - 10 = 4
14) n - 2 = 8
15) n - 2 = 9
16) 2n - 3 = 17
17) 2n - 10 = 22
18) 3n - 6 = 13
19) 2n - 9 = 7
20) 2(n < 3) = 13
Step-by-step explanation:
I'm not entirely sure about numbers 10 and 20..
0.6+1.9= 2.5 is the result.
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
Answer:
proportional bc all of them are 1 shirt = 12.95