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2 years ago

Find y if y = -7x -23 and x = 10

Mathematics

1 answer:

denis-greek [22]2 years ago

6 0

Answer:

y=-93

Step-by-step explanation:

You just substitute 10 for x

y=-7(10)-23

y=-70-23

y=-93

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The graph of an absolute value function opens down and has a vertex of (0, -3). The domain of the function is . The range of the

Firdavs [7]

Answer:

Domain: All real numbers

Range: $y\leq -3$

Step-by-step explanation:

The domain is the set of all x values. The quadratic equation continue to operate over all x-values in both directions. The domain is all real numbers.

The range is the set of all y-values. Here the quadratic begins at -3 and continues in a downward direction forever. Then range is $y\leq -3$

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3 years ago

Which property or properties of arithmetic do you use when you calculate 3×70 by first calculating 3×7 = 21 and then putting a z

ANEK [815]

The property used is the Associative property

3 × 70 = 3(70) = 3 (7×10) = (3×7) ×10

The formula is

a × bc = a (bc) = a (b×c) = (a×b) ×c

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3 years ago

1. What is the median of the data represented in the line plot below? 0 1 2 3

Strike441 [17]

The median is 1 because that is the number in the middle

3 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

Solve for x. x^2−3x−70=0 x^2 is x to the second power

timurjin [86]

X² − 3x − 70=0
x² + 7x - 10x − 70=0
x(x+7) - 10(x+7) = 0
(x+7)(x-10) = 0

x + 7 = 0 or x - 10 = 0
x = -7 x = 10

Answer: x=-7, x=10

3 0

3 years ago

Read 2 more answers