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3 years ago

13

I need help immediately

1 answer:

melamori03 [73]3 years ago

7 0

Answer:

Ima say A

Step-by-step explanation:

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3^-6x(3^3 divide 3^0)^2

Greeley [361]

Answer:

${3}^{2}$

Step-by-step explanation:

$3^{ - 6} \times (3^4 \div 3^0)^2$

$\frac{1}{ {3}^{6} } \times ( {3}^{4} \div {3}^{0} {)}^{2}$

$\frac{1}{729} \times ( {3}^{4} \div {3}^{0} {)}^{2}$

$\frac{1}{729} \times ( {3}^{4} {)}^{2}$

$\frac{1}{729} \times 6561$

$\frac{1}{729} \times (729(9))$

$9$

${3}^{2}$

<h3>Hope it is helpful...</h3>

8 0

3 years ago

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

5 0

3 years ago

Read 2 more answers

6=x/4-8 for x what equation do you get after adding 8 to each side

Lena [83]

Answer:

After adding 8 you get 14 = x/4.

Step-by-step explanation:

6=x/4-8 Add 8 to both sides:

6 + 8 = x/4 - 8 + 8

14 = x/4

x = 4*14

x = 56.

6 0

3 years ago

Solve the equation 1/2(16x – 6) = 2.

Lorico [155]

Answer:

x = 0.625 or 5/8

Step-by-step explanation:

1/2(16x-6) = 2

8x - 3 = 3

8x = 3 + 3

8x/8 = 9/8

x = 0.625

can you mark me as brainliest

6 0

3 years ago

Directions: Simplify these problems by combining like terms.

Verdich [7]

Answer:

6s + 2s - 3s - 6:

5s-6

10t - 4t -6 + 5t:

11t-6

18r + 18r + 9r - 3r:

42r

20 - 4q + 40r - 16:

-4q+40r+4

17st - 16s + t:

17st-16s+t

. 101+101x - x:

101+100x

16a2 - 14a + a2 - 3a:

14 ato the power of 2- 17a

14t + 14t + t:

29t

r + s + rs + s + rs + s:

r+2rs+3s

54 pt - 3p + 4t - 3pt:

51pt-3p+4t

i dont know 11

101c - 5c +4c:

100c

12q - 4 + 10q - 4q +9:

18q+5

21k - 20k + 3k:

4k

181x + 91x - 23x:

249x

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers