The sides are 2x, 3x-5 and 4x+2
perimiter is the sum of the sides
a.
2x+3x-5+4x+2=63 is an equation
b.
solve
group like terms
2x+3x+4x-5+2=65
add like terms
9x-3=65
add 3 to both sides
9x=68
divide both sides by 9
x=68/9
2x=2(68/9)=136/9 in
3x-5=3(68/9)-5=(68/3)-5=(68/3)-(15/3)=53/3
4x+2=4(68/9)+2=272/9+2=272/9+18/2=290/9
the side lengths are 136/9in, 53/3in, and 290/9in
Answer:
48∛9 ft²
Step-by-step explanation:
The length (L) and width (W) are given by:
![L = 4\sqrt[3]{24}\\ W= 6\sqrt[3]{3}](https://tex.z-dn.net/?f=L%20%3D%204%5Csqrt%5B3%5D%7B24%7D%5C%5C%20W%3D%206%5Csqrt%5B3%5D%7B3%7D)
Since this is a rectangular region, the area is given by:
![A=L*W=L \\A=4\sqrt[3]{24}* 6\sqrt[3]{3}\\A=24\sqrt[3]{72}\ ft^2](https://tex.z-dn.net/?f=A%3DL%2AW%3DL%20%5C%5CA%3D4%5Csqrt%5B3%5D%7B24%7D%2A%206%5Csqrt%5B3%5D%7B3%7D%5C%5CA%3D24%5Csqrt%5B3%5D%7B72%7D%5C%20ft%5E2)
The answer can be further simplified by factoring as follows:
![A=24\sqrt[3]{72} = \\A=24\sqrt[3]{2*2*2*3*3}= 24\sqrt[3]{2^3*9}\\A=48\sqrt[3]{9}\ ft^2](https://tex.z-dn.net/?f=A%3D24%5Csqrt%5B3%5D%7B72%7D%20%3D%20%5C%5CA%3D24%5Csqrt%5B3%5D%7B2%2A2%2A2%2A3%2A3%7D%3D%2024%5Csqrt%5B3%5D%7B2%5E3%2A9%7D%5C%5CA%3D48%5Csqrt%5B3%5D%7B9%7D%5C%20ft%5E2)
The exact area is its simplest form is 48∛9 ft²
Answer:
a =7.5
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2+ b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 + 10 ^2 = 12.5^2
a^2 + 100 =156.25
Subtract 100 from each side
a^2 = 56.25
Take the square root of each side
sqrt(a^2) = sqrt( 56.25)
a =7.5
Answer:
Change the positive numbers to negative and change the negative numbers to positive.
Step-by-step explanation:
I hope this helps u! :D
