Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor = 
or
The z factor = 
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
Answer:
A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more
Step-by-step explanation:
Option A Versus Option B
Option A Option B
Day Amount Deposited Day Amount Deposited
0 $40,000.00 0 $1.00
1 $40,250.00 1 $2.00
2 $40,500.00 2 $4.00
...
30 $47,500 16 $65,536.00
Answer:
A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more
SA=201.7cm^2
I used the equation
SA=pi^1/3(6*V)^2/3 in case you have any more questions like this
Plug in the points and see if y and x are equal to each other.
(2,3)
y= x-1
3= 2-1
3= 1 (not the solution)
y=3x
3=3*3
3=9 (not the solution)
y=x+1
3=2+1
3=3 (solution) We can check to make sure.
y=-3x
3=-3*3
3=-9 (not the solution)
y=x+1 <em>is the answer.
</em>
I hope this helps!
~kaikers
