Please Help Giving Brainliest!!!!! (05.06)Which net matches the solid figure shown below? A three-dimensional cube with a height
of 8 centimeters, a length of 6 centimeters, and a width of 3 centimeters.
A net is shown with 3 rectangles attached side by side all with width 8 centimeters and length 6 centimeters. Attached to the middle rectangle above is a rectangle with a length of 6 centimeters and a width of 3 centimeters. Attached to the middle rectangle and underneath are 2 more rectangles with the same length. The widths of these rectangles are 8 centimeters and 3 centimeters.
A net is shown with 3 rectangles attached side by side all with width 3 centimeters. The lengths of the triangles are 8 centimeters, 6 centimeters, and 8 centimeters. Attached to the middle rectangle underneath are 3 more rectangles with the same length. The widths of these rectangles are 3 centimeters, 8 centimeters, and 8 centimeters.
A net is shown with 3 rectangles attached side by side all with width 3 centimeters and length 6 centimeters. Attached to the middle rectangle above is a rectangle with a width of 8 centimeters. Attached to the middle rectangle and underneath are 2 more rectangles with the same length with widths of 8 centimeters and 3 centimeters.
A net is shown with 3 rectangles attached side by side all with width 3 centimeters. The length of the first and third rectangle is 8 centimeters and the middle is 6 centimeters. Attached to the middle rectangle underneath are 3 more rectangles with the same length. The widths of these rectangles are 8 centimeters, 3 centimeters, and 8 centimeters.
A net is shown with 3 rectangles attached side by side all with width 8 centimeters and length 6 centimeters. Attached to the middle rectangle above is a rectangle with a length of 6 centimeters and a width of 3 centimeters. Attached to the middle rectangle and underneath are 2 more rectangles with the same length. The widths of these rectangles are 8 centimeters and 3 centimeters.
A net is shown with 3 rectangles attached side by side all with width 3 centimeters. The lengths of the triangles are 8 centimeters, 6 centimeters, and 8 centimeters. Attached to the middle rectangle underneath are 3 more rectangles with the same length. The widths of these rectangles are 3 centimeters, 8 centimeters, and 8 centimeters.
A net is shown with 3 rectangles attached side by side all with width 3 centimeters and length 6 centimeters. Attached to the middle rectangle above is a rectangle with a width of 8 centimeters. Attached to the middle rectangle and underneath are 2 more rectangles with the same length with widths of 8 centimeters and 3 centimeters.
A net is shown with 3 rectangles attached side by side all with width 3 centimeters. The length of the first and third rectangle is 8 centimeters and the middle is 6 centimeters. Attached to the middle rectangle underneath are 3 more rectangles with the same length. The widths of these rectangles are 8 centimeters, 3 centimeters, and 8 centimeters.
1 answer:
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The given function is
f(x) = x - ln(8x), on the interval [1/2, 2].
The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²
A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079
The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.
Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)
f(x) = x - ln(8x), on the interval [1/2, 2].
The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²
A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079
The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.
Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)