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Alisiya [41]
3 years ago
13

In algebra how do i convert y-7=-2/3(x+1) into standard form and what would it be?

Mathematics
1 answer:
Art [367]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Where, if at all possible,

A

,

B

, and

C

are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

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How many subsets are there of set A
nignag [31]
You didn’t add a picture, so it’s impossible to answer
5 0
3 years ago
The probability that an electronic device produced by a company does not function properly is equal to 0.1. If 10 devices are bo
coldgirl [10]

Answer:

Correct option: A. P=0.057

Step-by-step explanation:

<u>Binomial Distribution</u>

The binomial distribution fits the case of n independent events each one with a probability of success equal to p where k successes have been achieved.

The PMF (Probability Mass Function) of the binomial distribution is

\displaystyle P(k,n,p)=\binom{n}{k}p^kq^{n-k}

Where q = 1-p

The individual probability that an electronic device does not function properly is p=0.1. We know n=10 devices have been bought and we want to compute the probability that 7 devices function properly. Please notice that this is not the value of k since p is the probability of failure. The correct value of k=10-7=3. The required probability is

\displaystyle P(3,10,0.1)=\binom{10}{3}0.1^30.9^{10-3}

\boxed{P=0.057}

8 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
Your grandparents invested $2,000 for you on the day you were born. How much will this investment be worth on your 25th birthday
algol [13]

We know that, Amount in Compound interest is given by :

\bigstar \ \ \boxed{\sf{Amount = Principal\bigg(1 + \dfrac{Rate \ of \ Interest}{100}\bigg)^{Time \ Period}}}

Given : Principal = $2000

Given : Annual yield is 5% and the interest is compounded quarterly

It means : Interest is compounded 4 times in a year

\implies \sf{Rate \ of \ Interest = \dfrac{R}{4} = \dfrac{5}{4}}

\sf{\implies Time \ period = (25 \times 4) = 100}

Substituting all the values in the formula, we get :

\implies \sf{Amount = 2000\bigg(1 + \dfrac{\dfrac{5}{4}}{100}\bigg)^{100}}

\implies \sf{Amount = 2000\bigg(1 + \dfrac{5}{400}\bigg)^{100}}

\implies \sf{Amount = 2000\bigg(1 + \dfrac{1}{80}\bigg)^{100}}

\implies \sf{Amount = 2000\bigg(\dfrac{81}{80}\bigg)^{100}}

\implies \sf{Amount = 2000 \times (1.0125)^{100}}

\implies \sf{Amount = 2000 \times 3.463}}

\implies \sf{Amount = 6926.8}

8 0
3 years ago
Kyle walks 3 blocks south from his home to school, and jana walks 2 blocks north from her home to kyle's home. how far and in wh
Nostrana [21]
If Jana has to walk 2 blocks north to get to Kyle's home, then 3 blocks south to get to school, this means that she has just retraced the 2 blocks she walked to get to Kyle's home.

So the school is just 1 block south of Jana's home.
6 0
3 years ago
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