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Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is .
The lateral surface area of the triangular pyramid is
cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
Answer:
I. 60%
II. 75.4 kg
Step-by-step explanation:
We will use the z-scores and the standard normal distribution to answer this questions.
We have a normal distribution with mean 69 kg and variance 25 kg^2 (therefore, standard deviation of 5 kg).
I. What percentage of adult male in Boston weigh more than 72 kg?
We calculate the z-score for 72 kg and then calculate the associated probability:
II. What must an adult male weigh in order to be among the heaviest 10% of the population?
We have to calculate tha z-score that satisfies:
This happens for z=1.28 (see attachment).
Then, we can calculate the weight using this transformation:
