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Valentin [98]
3 years ago
6

The ABC Book Club charges a $40 monthly fee, plus $2 per book read in that month. The Easy Book Club charges a 35$ monthly fee,

plus 3$ per book read in that month. For each club, how many books must be read in 1 month for the total charges from each club to be equal.
Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0
The expression for the cost of the ABC Book Club is 2x + 40. The expression for the cost of the Easy Book Club is 3x + 35. To find when the total charge for both book clubs is equal, the two expressions must equal each other. (x = the number of books read)

2x + 40 = 3x + 35

Subtract 35 from both sides.

2x + 5 = 3x

Subtract 2x from both sides.

5 = x

So, the total charge for each club is equal when 5 books are read.
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EleoNora [17]

Answer:

△ABX ≅ △ACY, by reason that they are equal and congruent to each other.

I hope this answers your question.

6 0
3 years ago
Mr. Keller bought a car for $20,000. A study shows that a car will depreciate (go DOWN in value) by 15% each year. How much is M
Schach [20]
A: the formula would be f(x) = P(R) ^T or f(x) = Principle(rate)^time

B: f(x) = 20,000(0.85)^5  

C: = 8,874.10625

D: Yes, the final answer makes sense compared to the origional cost of the car in relation to the formula. As well, time decreases the value of a car, so for the cost to be so low only makes sense due to the cars decrease in value or an extended and elongated amount of time. 

E: You can solve this equation graphically by plotting th point at 20,000 and then taking 85% of 20,000 and plotting it each time until you get to the fifth year.

5 0
3 years ago
Read 2 more answers
Seven pounds of grapes cost $10.43 how much would it cost for 3 pounds
lozanna [386]
1. Divide $10.43 by 7 to find out how much each pound of grapes costs.
$10.43/7=$1.49
2. Multiply $1.49 by 3 to find out how much 3 pounds of grapes would cost.
$1.49•3=$4.47
3. So, 3 pounds of grapes would cost $4.47

Hope this helps!
4 0
3 years ago
At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi
alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

- The traditional method is distributed X ~ Poisson(L = 1)

- The new method is distributed X ~ Poisson(L = 5)

P(X=x)=\frac{L^{x}e^{-L}}{x!}

Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events  (to send 5 letters) in a unit of time for both methods, so:

- For the traditional method:

P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367

- For the new method:

P(X=5)=\frac{5^{5}e^{-5}}{5!}\\\\P(X=5) = 0.175

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.

7 0
3 years ago
What is 2 tens 13 ones
ohaa [14]
2 tens = 20
13 ones = 13

20 + 13 = 33

33 is your answer

hope this helps
7 0
3 years ago
Read 2 more answers
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